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Major elimination product if the given compounds is heated with strong base is $C_{2} H_{5} - C H = C H - {C H}_{3} (t r a n s)$ .

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Solution

When (1-bromopropyl)benzene is heated with strong base, it undergoes dehydrobromination to form (E)-prop-1-enylbenzene. The trans alkene is more stable than cis alkene. Moreover in the given compound, the carbon carbon double bond is in conjugation with aromatic nucleus.

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