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Reaction with Metals

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When ${C l}_{2}$ gas is passed into a mixture containing ${B r}^{-}$ and $I^{-}$ and ${C H C l}_{3}$ , $I_{2}$ (violet) first apears in ${C H C l}_{3}$ layer.

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Solution

When ${C l}_{2}$ gas is passed into a mixture containing ${B r}^{-}$ and $I^{-}$ and ${C H C l}_{3}$ , $I_{2}$ (violet) first apears in ${C H C l}_{3}$ layer.
The decreasing order for the reducing power of halide ions is $I^{-} > {B r}^{-} > {C l}^{-} > F^{-}$
Thus, chlorine can displace bromine and iodine fromn their salts.
Silmilarly bromine can displace iodine from its salt.
${2 I}^{-} + {C l}_{2} ⟶ {2 C l}^{-} + I_{2}$
${2 B r}^{-} + {C l}_{2} ⟶ {2 C l}^{-} + {B r}_{2}$
Thus, $I_{2}$ is formed in preference of ${B r}_{2}$ . Iodine is violet in colour. Hence, ${C H C l}_{3}$ layer appears violet. Hence, the given statement is true.

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