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Van der Waal's constant for attraction for $N H_{3}$ is greater than $C O_{2}$ .
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Solution

The correct option is A 1
The vander Waals gas equation is $(\begin{matrix} P + \frac{a}{V^{2}} \end{matrix}) (V - b) = R T$

where $P$ is the pressure, $V$ is molar volume and $T$ is the temperature of the given sample of gas. $R$ is called molar gas constant, $a$ and $b$ are called vander Walls constants.

For $N H_{3}$
$a = 4.17; b = 0.0371$

For $C O_{2}$
$a = 3.59; b = 0.0427$

So, van der Waal's constant for attraction (a) for $N H_{3}$ is greater than $C O_{2}$

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