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Question

If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178. and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then if all the 9 numbers are arranged in ascending order , the sum of the smallest and largest number is


A

15

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B

16

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C

17

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D

18

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Solution

The correct option is A

15


Let the odd numbers be x,x+2,x+4,x+6 and x+8.
Their Sum = 5x+20
Let the even numbers be y,y+2,y+4 and y+6.
Their Sum = 4y+12
Given that:
2(5x+20)+3(4y+12)=178 and
3(5x+20)+2(4y+12)=177
Simplifying the above two equations, we get
5x+6y=51 ...(1)
15x+8y=93 ...(2)
Multiplying (1) by 3,
15x+18y=153 ...(3)
Subtracting (2) from (3), we get
10y=60y=6
Substituting y=6 in (1), we get x=3.
Therefore, the odd numbers are 3, 5, 7, 9, 11
and the even numbers are 6, 8, 10, 12.

Arranging them in ascending order,
the numbers are 3,5,6,7,8,9,10,11,12.

Hence the required sum = 3 + 12 = 15


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