Question

If twice x is 40 more than y, then (x -21) $\frac{y}{2}$,(where x and y are Natural numbers).

• A. >
• B. <
• C. =

Answer 1

The correct option is B <

Twice x is 40 more than y.
Hence, 2x > y + 40
$\Rightarrow$ x > $\frac{y}{2}$ + 20.
Subtracting 21 from both sides,
$\Rightarrow$ (x - 21) > $\frac{y}{2}$ -1.