If twice x is 40 more than y- then x-21 y-2- where x and y are Natural numbers-A- -B- -C -

The correct options are A gt; B lt;Twice x is 40 more than y. Hence, 2x gt; y + 40 ⇒ x gt; y/2 + 20. Subtracting 21 from both sides, ⇒ (x 21) ...

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Standard VII

Mathematics

Inequations

If twice x is...

Question

If twice x is 40 more than y, then (x -21) $\frac{y}{2}$ ,(where x and y are Natural numbers).

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Solution

The correct options are
A >
B <
Twice x is 40 more than y.
Hence, 2x > y + 40
$\Rightarrow$ x > $\frac{y}{2}$ + 20.
Subtracting 21 from both sides,
$\Rightarrow$ (x - 21) > $\frac{y}{2}$ -1.

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If twice x is 40 more than y, then (x -21) y2,(where x and y are Natural numbers).

The correct options are A > B <Twice x is 40 more than y. Hence, 2x > y + 40 ⇒ x > y2 + 20. Subtracting 21 from both sides, ⇒ (x - 21) > y2 -1.

If twice x is 40 more than y, then (x -21) $\frac{y}{2}$ ,(where x and y are Natural numbers).

The correct options are
A >
B <
Twice x is 40 more than y.
Hence, 2x > y + 40
$\Rightarrow$ x > $\frac{y}{2}$ + 20.
Subtracting 21 from both sides,
$\Rightarrow$ (x - 21) > $\frac{y}{2}$ -1.