Question

If two angles of a triangle are equal, then prove that sides opposite to them are also equal.

Answer 1

$\angle C=\angle B$

In $△ABD$ & $△ACB$

$\angle B=\angle C$ (Given)

$\angle BAD=\angle CAD$ (construction)

$AD=AD$

$△ABD\cong △ACD$

$AB=AC$