If two balls each of mass 0.06 kg moving in opposite directions with speed of $4 m s^{- 4}$ collide and rebound with same speed, then the impulse imparted to each ball due to other is:

0.48 k g m s^{- 1}

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0.53 k g m s^{- 1}

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0.8 k g m s^{- 1}

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0.92 k g m s^{- 1}

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Solution

The correct option is A $0.48 k g m s^{- 1}$
Mass = $0.06 k g$

Velocity= $4 m / s$

Rebound velocity = $- 4 m / s$

Impulse = change in momentum

Impulse = $m (u) - m (v)$

Impulse = $0.06 \times 4 - (0.06 \times - 4)$

Impulse = $0.24 - (- 0.24)$

Impulse = $0.24 + 0.24$

Impulse = $0.48 k g m / s$

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If two balls each of mass 0.06 kg moving in opposite directions with speed of 4ms−4 collide and rebound with same speed, then the impulse imparted to each ball due to other is:

The correct option is A 0.48kgms−1Mass = 0.06kgVelocity= 4m/sRebound velocity = −4m/sImpulse = change in momentum Impulse = m(u)–m(v)Impulse = 0.06×4–(0.06×−4)Impulse = 0.24–(−0.24)Impulse = 0.24+0.24Impulse = 0.48kgm/s

If two balls each of mass 0.06 kg moving in opposite directions with speed of $4 m s^{- 4}$ collide and rebound with same speed, then the impulse imparted to each ball due to other is: