If two balls each of mass 0.6 kg moving in opposite directions with speed of 4 m s $^{- 1}$ collide and rebound with same speed, then the impulse imparted to each ball due to other is:

0.48 k g m s^{- 1}

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0.53 k g m s^{- 1}

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0.81 k g m s^{- 1}

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0.92 k g m s^{- 1}

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Solution

The correct option is A $0.48 k g m s^{- 1}$
Impulse
$= F \times t =$ change in momentum
$=$ 0.06 (4-(-4))
$=$ 0.48 kg m s $^{- 1}$

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If two balls each of mass 0.6 kg moving in opposite directions with speed of 4 m s−1 collide and rebound with same speed, then the impulse imparted to each ball due to other is:

The correct option is A 0.48kgms−1Impulse=F×t= change in momentum= 0.06 (4-(-4))= 0.48 kg m s−1

If two balls each of mass 0.6 kg moving in opposite directions with speed of 4 m s $^{- 1}$ collide and rebound with same speed, then the impulse imparted to each ball due to other is:

The correct option is A $0.48 k g m s^{- 1}$
Impulse
$= F \times t =$ change in momentum
$=$ 0.06 (4-(-4))
$=$ 0.48 kg m s $^{- 1}$