If two bars in a histogram have unequal widths but the same height, then which class interval will have a higher density of observations?

The one with higher class width

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The one with lower class width

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both have same density

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Can't say

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Both have same density

The density of observations doesn't depend on upon the widths of the histogram, height of the histogram is proportional to its frequency. So, both will have the same density of observations.

Suggest Corrections

Similar questions

If two bars in a histogram have unequal widths but the same height, then which class interval will have a higher number of observations?

If two classes of different widths have the same number of observations, then the bigger class will have a bar with a smaller height in a histogram.

The height of the bars in a histogram represents the frequency of the data (in the considered class interval) and width of the histogram represents class width.

Q. When in a frequency distribution class widths are not same we have to draw histogram then,

The height of a histogram represents the frequency of the data of a class interval and width of the histogram represents class width.

Join BYJU'S Learning Program

If two bars in a histogram have unequal widths but the same height, then which class interval will have a higher density of observations?

The correct option is C Both have same density The density of observations doesn't depend on upon the widths of the histogram, height of the histogram is proportional to its frequency. So, both will have the same density of observations.

The correct option is C
Both have same density

The density of observations doesn't depend on upon the widths of the histogram, height of the histogram is proportional to its frequency. So, both will have the same density of observations.