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Question

If two chords AB and CD intersect externally at P and if AB = 4, PB = 5, PD = 3, then CD =


A

4.3

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B

4

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C

1.5

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D

1.3

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Solution

The correct option is D

1.3



According BPT

We have,

PCCD=PBBA

PCCD=54

Since PC = PD - CD

PDCDCD=54

4(PDCD)=5CD

4PD4CD=5CD

4PD=5CD+4CD

4PD=9CD

4(3)=9CD (Given PD = 3cm)

12=9CD

CD=129

CD=43=1.3


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