If two chords AB and CD intersect externally at P then PA x PB =
PD X PD
2(PC x PD)
PC x PD
PC X PC
If two chords AB and CD intersect internally at P and if PA = 5, PB = 4, PD = 2, then PC =
In the given figure chords AB and CD intersect at P. If PA = x, PB =9cm, PC =5 cm and PD = 8.1cm, find the value of ‘x’.