Question

If two chords AB and CD intersect internally at P and if PA = 5, PB = 4, PD = 2, then PC =

• A. 12
• B. 22
• C. 10
• D. 20

Answer 1

The correct option is C

10

If two chords intersect internally, then the product of their segments are equal.

$\therefore$ $PA\times PB=PC\times PD$

$\therefore$ $5\times 4=PC\times 2$

$\therefore$ PC = $\frac{20}{2}$

= 10