Question

If two coins are tossed $5$ times, what is the chance that there will be $5$ heads and $5$ tails?

Answer 1

Two coins are tossed five times

So possible number of outcomes $=2^{10}=1056$

Number of ways in which $5$ heads and $5$ tails come $=\frac{10!}{5!5!}=364$

$\therefore$ Required probability $=P\left(E\right)=\frac{364}{1056}=\frac{63}{256}$