Question

If two coins are tossed. Then find the probability of the following events
Getting no head

Answer 1

When two different coins are tossed randomly, the sample space is given by

$S=\{HH,HT,TH,TT\}$

$\therefore ,n\left(S\right)=4$.

Let $E=$ event of getting no head. Then,

$E=\left\{TT\right\}$ and, $\therefore ,n\left(E\right)=1$.

$\therefore ,P\left(gettingnohead\right)=P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{1}{4}$