Question

If two consecutive sides of a rhombus are represented by $(5x+10)$ and $(3x+14)$, then the perimeter of the rhombus is

• A. 24 units
• B. 80 units
• C. 60 units
• D. 40 units

Answer 1

The correct option is B 80 units

We know that all sides of a rhombus are equal.
$\therefore 5x+10=3x+14$
$\Rightarrow 5x–3x=14–10$
$\Rightarrow 2x=4$
$\Rightarrow x=2$
$\therefore$ Side of rhombus $=5x+10$
$=5\left(2\right)+10$
$=20$ units
$\therefore$ Perimeter of rhombus $=4\times \text{Side}$
$=4\times 20$
$=80$ units
Hence, the correct answer is option (b).