If two cuboids of dimensions 3 cm ? 3 cm ? 6 cm are placed height by height, what would be the dimensions of the resulting figure be?

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Solution

Dear Student,

$D i m e n t i o n o f 1 c u b o i d = 3 \times 3 \times 6 H e n c e l e n g t h = 3 c m, b r e a d t h = 3 c m a n d h e i g h t = 6 c m N o w w h e n 2 c u b o i d s a r e p l a c e d s i d e b y s i d e t h e h e i g h t w i l l r e m a i n s a m e a s 6 c m a s t h e y a r e n o t p l a c e d o n t o p o f e a c t o t h e r T h e b r e a d t h w i l l r e m a i n s a m e a s 3 c m B u t l e n g t h w i l l b e a d d e d f o r 2 c u b o i d s a s 3 \times 2 = 6 H e n c e d i m e n s t i o n s o f r e s u l t i n g c u b o i d a r e 6 \times 3 \times 6 c m$

Regards,

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