If two diagonals of an isosceles trapezium are $2 x c m$ and $(3 x + 2) c m$ . Find the value of $x$ .

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Solution

The correct option is B 2
Diagonals of an isosceles trapezium are equal in length.
So,
$2 x = 3 x + 2 3 x - 2 x = 2 x = 2$

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Similar questions

3 x c m

(2 x + 2) c m

x

x = 3 + 2 \sqrt{2}

(\sqrt{x} - \frac{1}{\sqrt{x}}) .

Prove that the diagonals of an isosceles trapezium are equal.

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