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Question

If two diameters of a circle intersect each other at right angles, then quadrilateral formed by joining their end points is a


A

rhombus

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B

rectangle

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C

parallelogram

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D

square

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Solution

The correct option is D

square


Given that the two diameters AB and CD of a circle intersect each other at right angles.

AD, DB, BC and CA are joined forming a quadrilateral ABCD.

The diagonals are equal and bisect each other at right angles.

ACBD is a square.


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