Question

If two diameters of a circle intersect each other at right angles, then the quadrilateral formed by joining their end points is a:

• A. Rhombus
• B. Rectangle
• C. Square
• D. Parallelogram

Answer 1

Answer: (C)

Square

Let $AB$ and $CD$ be the diagonals of a circle such that $AB\perp CD$
Joining points $A,b,C,D$ in order we see that $AB$ and $CD$ are the equal diagonals of quad. $ACBD$ which intersect at rightangle.
$\therefore$ $ACBD$ is a square.