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Question

If two different tangents of y2=4ax are normals to x2=4y, then

A
|a|>22
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B
|a|<22
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C
|a|>122
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D
|a|<122
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Solution

The correct option is A |a|>22
The tangent to the parabola y2=4ax is y=m1x+am1 ...(1)
The normal to the parabola x2=4y is x=m2y2m2(m2)3 ...(2)
comparing equation (1) and (2)
m1=1m2 & am1=2+(m2)2
(m2)2am2+2=0
For two distinct tangents/normals
D>0
a28>0
|a|>22

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