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Question

If two different tangents of y2=4x are the normals to x2=4by then

A
|b|>122
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B
|b|<122
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C
|b|>12
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D
|b|<12
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Solution

The correct option is B |b|<122
Tangent to y2=4x in terms of m is
y=mx+1m

Normal to x2=4by in terms of m is
y=mx+2b+bm2
If these are same lines, then
1m=2b+bm2
2bm2m+b=0
For two different tangents, D>0
18b2>0
|b|<122

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