wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

If two genes 'a' and 'b' are linked and show 20% recombination, the proportion of gemetes produced in F1 by a dihybrid ++/ab derived from a cross between ++/++ and ab/ab would be

A
++ 20% : ab 20% : + a 20% : +b 20%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
++ 80% : ab 20%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
++ 50% : ab 50%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
++ 40% : ab 40% : +a 10% : +b 10%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D ++ 40% : ab 40% : +a 10% : +b 10%
As per the question, 20% recombination is present in genes 'a' and 'b' , so this shows 20% crossover and thus resultant progeny will be recombinants of both the parents. The linkage percentage here is 80% that means there will be 40% chances for progeny to be identical to both the parents.
So the correct answer is ' D'.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon