If two horizontal forces $F_{1}$ and $F_{2}$ of the unequal magnitude act on a body in opposite directions then find the net force acting on the body.

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Solution

The situation is shown in the above diagram. Here we have considered $F_{1} > F_{2}$ . $F_{1}$ acts towards right and $F_{2}$ acts towards left.
The net force acting on the body is $F_{n e t} = F_{1} - F_{2}$ (towards right).

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If two horizontal forces F1 and F2 of the unequal magnitude act on a body in opposite directions then find the net force acting on the body.

The situation is shown in the above diagram. Here we have considered F1>F2. F1 acts towards right and F2 acts towards left.The net force acting on the body is Fnet=F1−F2 (towards right).

If two horizontal forces $F_{1}$ and $F_{2}$ of the unequal magnitude act on a body in opposite directions then find the net force acting on the body.

The situation is shown in the above diagram. Here we have considered $F_{1} > F_{2}$ . $F_{1}$ acts towards right and $F_{2}$ acts towards left.
The net force acting on the body is $F_{n e t} = F_{1} - F_{2}$ (towards right).