If two identical bar magnets, each of length $l$ , pole strength $m$ and magnetic moment $M$ are placed perpendicular to each other with their unlike poles in contact, the magnetic moment of the combination is

\frac{M}{\sqrt{2}}

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l m (\sqrt{2})

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2 l m (\sqrt{2})

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2 M

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Solution

The correct option is B $l m (\sqrt{2})$
Magnetic Moment = $M$ =Magnetic Length \times Pole Strength = $m l$
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} + M^{2} + 2 M^{2} cos 90^{o}}$ (angle between the vectors would be $90^{o}$ )
$M = \sqrt{2} M = \sqrt{2} m l$

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If two identical bar magnets, each of length l, pole strength m and magnetic moment M are placed perpendicular to each other with their unlike poles in contact, the magnetic moment of the combination is

The correct option is B lm(√2)Magnetic Moment = M =Magnetic Length \times Pole Strength =mlM=√M21+M22+M1M2cosθM=√M2+M2+2M2cos90o (angle between the vectors would be 90o )M=√2M=√2ml

If two identical bar magnets, each of length $l$ , pole strength $m$ and magnetic moment $M$ are placed perpendicular to each other with their unlike poles in contact, the magnetic moment of the combination is

The correct option is B $l m (\sqrt{2})$
Magnetic Moment = $M$ =Magnetic Length \times Pole Strength = $m l$
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} + M^{2} + 2 M^{2} cos 90^{o}}$ (angle between the vectors would be $90^{o}$ )
$M = \sqrt{2} M = \sqrt{2} m l$