If two jobs A and B can be done independentely by m and n ways respectiveley, then the number of ways by which job A and job B can be done?
A
(m+n)
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B
(m+n)(m+n)
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C
(m×n)
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D
(m+n)(m×n)
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Solution
The correct option is C(m×n) Here we can see that for each different ways in which job A can be done, job B can be done in n different ways. So, job A and job B can be done in (m×n)ways. Option (c) is correct