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Standard XII

Physics

Archimedes' Principle

If two liquid...

Question

If two liquids of same mass but densities $d_{1}$ and $d_{2}$ respectively are mixed, then density of mixture is given by:

d = \frac{d_{1} + d_{2}}{2}

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d = \frac{d_{1} + d_{2}}{2 d_{1} d_{2}}

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d = \frac{2 d_{1} d_{2}}{d_{1} + d_{2}}

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d = \frac{d_{1} d_{2}}{d_{1} + d_{2}}

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Solution

The correct option is C $d = \frac{2 d_{1} d_{2}}{d_{1} + d_{2}}$
$m = v_{1} d_{1} = v_{2} d_{2}$
$v = v_{1} + v_{2}$
$\frac{2 m}{d} = \frac{m}{d_{1}} + \frac{m}{d_{2}}$
$d = \frac{2 d_{1} d_{2}}{d_{1} + d_{2}}$

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If two liquids of same mass but densities d1 and d2 respectively are mixed, then density of mixture is given by:

The correct option is C d=2d1d2d1+d2m=v1d1=v2d2v=v1+v22md=md1+md2d=2d1d2d1+d2

If two liquids of same mass but densities $d_{1}$ and $d_{2}$ respectively are mixed, then density of mixture is given by:

The correct option is C $d = \frac{2 d_{1} d_{2}}{d_{1} + d_{2}}$
$m = v_{1} d_{1} = v_{2} d_{2}$
$v = v_{1} + v_{2}$
$\frac{2 m}{d} = \frac{m}{d_{1}} + \frac{m}{d_{2}}$
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