Question

If two moles of an ideal gas at $546K$ occupies a volume of $44.8$ litres, the pressure must be :

• A. $2atm$
• B. $3atm$
• C. $4atm$
• D. $1atm$

Answer 1

Answer: (A)

$2atm$

As we know, the ideal gas equation is $PV=nRT$

By putting all those given values, we get :

$P$ = $\frac{2\times 0.082\times 546}{44.8}$

$P$ = $1.99875=2$ $atm$

So, the correct option is $A$.