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Assigning Oxidation Numbers

If two moles ...

Question

If two moles of $K M n O_{4}$ oxidises $3$ moles of $M^{x +}$ to $M O_{3}^{-}$ in neutral medium. Find the value of $x$ .

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Solution

In neutral medium permangante ( $M n O_{4}^{-}$ ) reduces to $M n O_{2}$ . So the oxidation state of $M n$ changes $+ 7$ to $+ 4$ . So n-factor is $3$ .
Two mole of permangante reacts with $3$ moles of $M^{x +}$ .
Let the n -factor of $M^{x +}$ be $x$
Applying equivalence,
$2 \times 3 = 3 \times x$
$\Rightarrow x = 2$
so n-factor for $M^{x +}$ is $2$ .
$M^{x +} \to M O_{3}^{-}$
So the oxidation state of $M$ in $M O_{3}^{-}$ is $+ 5$
Hence, the value of $x$ is $5 - 2 = 3$

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