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Question

If two numbers are in the ratio 6 : 13 and their l.c.m. is 312, find the numbers.

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Solution

Let the two numbers be 'x' and 'y' such that x : y = 6 : 13 ⇒ xy = 613 .
We can assume that the HCF of 'x' and 'y' is a number 'k'.
So, x = 6k, and y = 13k.
Now, the product of any two numbers 'x' and 'y' is always equal to the product of their LCM and HCF
⇒ x×y = 312 × k
⇒ 6k × 13k = 312 × k
⇒ k = 3126×13 = 4
⇒ k = 4
Thus, x = 6k = 6 ×4 = 24, and y = 13 × 4 = 52.

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