If two of the zeroes of the polynomial f x - x 4-3 x 3- x 2-9 x -6 are -3 and -3 then all the zeroes areA- -3-3- 1-3B- -1-4- -3-3C- -3-3- 2-4D- -3-3- 1-2

The correct option is D √3, √3, 1, 2(x + √3)(x √3) = x2 3 will be a factor of f(x). Now divide f(x) by x2 ¬ 3 to get the quotient x2 3x + 2, which has ...

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Standard X

Mathematics

Factor Theorem

If two of the...

Question

If two of the zeroes of the polynomial f (x) = x⁴ - 3x³ - x² + 9x - 6 are - √3 and √3 then all the zeroes are

√3, - √3, 1, 3

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-1, 4, √3, - √3

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√3, - √3, 1, 2

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√3, - √3, 2, 4

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Solution

The correct option is C
√3, - √3, 1, 2

(x + √3)(x - √3) = x²- 3 will be a factor of f(x).

Now divide f(x) by x²¬ 3 to get the quotient x² - 3x + 2, which has the factors (x - 2)(x - 1).

Hence all the zeros are √3, - √3, 1, 2.

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If two of the zeroes of the polynomial f (x) = x4 - 3x3 - x2 + 9x - 6 are - √3 and √3 then all the zeroes are

The correct option is C √3, - √3, 1, 2(x + √3)(x - √3) = x2 - 3 will be a factor of f(x). Now divide f(x) by x2 ¬ 3 to get the quotient x2 - 3x + 2, which has the factors (x - 2)(x - 1). Hence all the zeros are √3, - √3, 1, 2.

If two of the zeroes of the polynomial f (x) = x⁴ - 3x³ - x² + 9x - 6 are - √3 and √3 then all the zeroes are

The correct option is C
√3, - √3, 1, 2

(x + √3)(x - √3) = x²- 3 will be a factor of f(x).

Now divide f(x) by x²¬ 3 to get the quotient x² - 3x + 2, which has the factors (x - 2)(x - 1).

Hence all the zeros are √3, - √3, 1, 2.