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Question

If two parallel lines are intersected by a transversal line, then the bisectors of the interior angles forms a:

A
square
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B
rectangle
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C
parallelogram
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D
trapezium
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Solution

The correct option is C rectangle
If two parallel lines are intersected by a transversal line, then the bisectors of the interior angles forms a rectangle.

To prove this, we will prove that the angle between two adjacent bisectors is 90°.

Let's start with bisectors of BAC and BAE. We know that the sum of these two angles is 180°.
Then the angle between the bisectors of these angles is
BAC2+BAE2=(BAC+BAE)2=180°2=90°.
Similarly, we can prove that the angle between the bisectors of ABC and ABD is 90°.

Now, let the bisectors of BAC and ABC intersect at point G.
We know that the sum of angles of a triangle is 180°. Using this fact,
AGB=180°(BAF+ABC)2
AGB=180°180°2=180°90°=90°
Similarly, we can prove that the angle between bisectors of BAE and ABD is 90°.
Since, all the angles formed by the bisectors of the interior angles are 90°, the bisectors of the interior angles forms a rectangle.

770634_98154_ans_f89b9cdcbf054172a772081bec7c2a44.png

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