If two parallel lines are intersected by a transversal line, then the bisectors of the interior angles forms a:
A
square
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B
rectangle
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C
parallelogram
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D
trapezium
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Solution
The correct option is C rectangle
If two parallel lines are intersected by a transversal line, then the bisectors of the interior angles forms a rectangle.
To prove this, we will prove that the angle between two adjacent bisectors is 90°.
Let's start with bisectors of ∠BAC and ∠BAE.
We know that the sum of these two angles is 180°.
Then the angle between the bisectors of these angles is ∠BAC2+∠BAE2=(∠BAC+∠BAE)2=180°2=90°.
Similarly, we can prove that the angle between the bisectors of ∠ABC and ∠ABD is 90°.
Now, let the bisectors of ∠BAC and ∠ABC intersect at point G.
We know that the sum of angles of a triangle is 180°. Using this fact, ∠AGB=180°−(∠BAF+∠ABC)2 ∠AGB=180°−180°2=180°−90°=90°
Similarly, we can prove that the angle between bisectors of ∠BAE and ∠ABD is 90°.
Since, all the angles formed by the bisectors of the interior angles are 90°, the bisectors of the interior angles forms a rectangle.