If two rectangles ABCD and PQRS whose sides are parallel to the coordinate axes are drawn as shown in below figure then the coordinates of 'R' are
(10,0)
Given B = (5,6)
Let E, F, G, H be the intersection points of these two rectangles.
Now AE = BF = 6 cm (∵ Opposite sides in a rectangle are equal)
∴ y-coordinate of F = y-coordinate of B - 6
= 6 - 6
= 0
and x-coordinate of F = x-coordinate of B (∵ BF is parallel to Y-axis)
∴ F = (5,0)
Given FR = 5 cm
∵ FR is parallel to X-axis, y-coordinate of F = y-coordinate of R
and x-coordinate R = x-coordinate of R + 5
= 5 + 5
= 10
∴ R = (10,0)