If two resistors of 25 - and 15 - are joined together in series and then placed in parallel with a 40 - resistor- the effective resistance of the combination isa 0-1 -b 10 -c 20 -d 40 -

nbsp;(c) 20 Omega; When 25 Omega; and 15 nbsp; Omega; are connected in series, then: Total resistance, R = 25 + 15 = 40 Ώ This 40 Ώ is connected i ...

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Standard X

Physics

Equivalent Resistance of a System of Resistor

If two resist...

Question

If two resistors of 25 Ω and 15 Ω are joined together in series and then placed in parallel with a 40 Ω resistor, the effective resistance of the combination is :

(a) 0.1 Ω
(b) 10 Ω
(c) 20 Ω
(d)40 Ω

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Solution

(c) 20 Ω
When 25 Ω and 15 Ω are connected in series, then:
Total resistance, R = 25 + 15 = 40 Ώ
This 40 Ώ is connected in parallel with the 40 Ώ resistor.
Therefore, the net resistance = 40 / 2 = 20 Ώ

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If two resistors of 25 Ω and 15 Ω are joined together in series and then placed in parallel with a 40 Ω resistor, the effective resistance of the combination is : (a) 0.1 Ω (b) 10 Ω (c) 20 Ω (d)40 Ω

(c) 20 Ω When 25 Ω and 15 Ω are connected in series, then: Total resistance, R = 25 + 15 = 40 Ώ This 40 Ώ is connected in parallel with the 40 Ώ resistor. Therefore, the net resistance = 40 / 2 = 20 Ώ

If two resistors of 25 Ω and 15 Ω are joined together in series and then placed in parallel with a 40 Ω resistor, the effective resistance of the combination is :

(a) 0.1 Ω
(b) 10 Ω
(c) 20 Ω
(d)40 Ω

(c) 20 Ω
When 25 Ω and 15 Ω are connected in series, then:
Total resistance, R = 25 + 15 = 40 Ώ
This 40 Ώ is connected in parallel with the 40 Ώ resistor.
Therefore, the net resistance = 40 / 2 = 20 Ώ