Question

If two roots of the equation $x^3-3x+2=0$ are same, then the roots will be

• A. 2, 2, 3
• B. 1, 1, -2
• C. - 2, 3, 3
• D. -2, -2, 1

Answer 1

The correct option is B

1, 1, -2

Given equation is $x^3-3x+2=0$

⇒ $x^2(x-1)+x(x-1)-2(x-1)=0$

⇒ $(x-1)(x^2+x-2)=0$ ⇒ $(x-1)(x-1)(x+2)=0$

Hence roots are 1, 1, -2