If two roots of the equation $x^{3} - 3 x + 2 = 0$ are same, then the roots will be

- 2, 3, 3

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-2, -2, 1

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2, 2, 3

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1, 1, -2

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Solution

The correct option is D
1, 1, -2

Given equation is $x^{3} - 3 x + 2 = 0$

⇒ $x^{2} (x - 1) + x (x - 1) - 2 (x - 1) = 0$

⇒ $(x - 1) (x^{2} + x - 2) = 0$ ⇒ $(x - 1) (x - 1) (x + 2) = 0$

Hence roots are 1, 1, -2

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If two roots of the equation $x^{3} - 3 x + 2 = 0$ are same, then the roots will be

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x^{3} - 4 x^{2} - p x + r = 0

x^{3} - 4 x^{2} - p x + r = 0

x^{3} - 3 x + q = 0

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