∵−√3,1+2i are the two roots of the given equation and coefficients are rational numbers.
⇒√3,1−2i are also roots of the given equation.
Let the remaining root be α.
Since, sum of roots equal to 1.
√3+(−√3)+(1+2i)+(1−2i)+α=1⇒α=−1
∴ The roots are −1,√3,1−2i,−√3,1+2i.
So, only one positive root i.e., √3