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Question

If two sides of a cyclic-quadrilateral are parallel; prove that :

(i) its other two sides are equal.

(ii) its diagonals are equal.

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Solution



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(i) Given AB \parallel DC

Therefore \angle BAC = \angle DCA (alternate angles)

Chord AD subtends \angle DCA on circumference.

Chord BC subtends \angle CAB on circumference.

Therefore AD = BC (since equal chords subtend equal angles on the circumference)

(ii) Consider \triangle ADB \ \ \& \ \  \triangle ABC

AB is common

AD = CB (proved above)

\angle ACB = \angle ADB (angles in the same segment)

Therefore \triangle ADC \cong \triangle ABC (by SAS axiom)

Therefore AC = DB (corresponding parts of congruent triangles are equal)

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