If two sides of a triangle are unequal, the greater side has the greater angle opposite to it. State whether the given statement is true or false.
True
Let consider a triangle ABC in which AB > AC.
From AB, cut AD = AC. Join C and D.
In ΔACD:
AC = AD (by construction) --------(1)
∠ACD = ∠ADC (Angle opposite to equal side) --------(2)
In ΔBDC
Ext . ∠ADC > ∠B (Ext. angle always greater than each of its interior opposite angles) --------(3)
∠ACD > ∠B ------------ From (2) and (3)
Hence, ∠ACB > ∠B
Therefore, ∠ACB > ∠ACD > ∠B
Thus, given statement is true.