If two sides of a triangle measure 4cm and 6cm find all possible measurements (positive Integers) of the third side.
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Solution
We know that the sum of two sides should be greater than the third side.
So, let the length of the third side be xcm. 4+x>6=x>2
and 4+6>x ⇒x<10
Hence, x=3,4,5,6,7,8,9