If two springs of spring constants $k_{1}$ and $k_{2}$ whose extensions upon applying a force F are $x_{1}$ and $x_{2}$ respectively are joined together in a series configuration, the net extension will be

x = F (1 / k_{1} + 1 / k_{2})

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x = F (1 / k_{1} - 1 / k_{2})

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x = F (k_{1} + k_{2})

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x = F (k_{1} - k_{2})

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Solution

The correct option is A $x = F (1 / k_{1} + 1 / k_{2})$
$x_{1} = F / k_{1}$ and $x_{2} = F / k_{2}$
Upon joining both the springs together, the net extension will be $x = x_{1} + x_{2}$
Substituting, we get, $x = F (1 / k_{1} + 1 / k_{2})$
The correct option is (a)

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If two springs of spring constants k1 and k2 whose extensions upon applying a force F are x1 and x2 respectively are joined together in a series configuration, the net extension will be

The correct option is A x=F(1/k1+1/k2)x1=F/k1 and x2=F/k2Upon joining both the springs together, the net extension will be x=x1+x2Substituting, we get, x=F(1/k1+1/k2)The correct option is (a)

If two springs of spring constants $k_{1}$ and $k_{2}$ whose extensions upon applying a force F are $x_{1}$ and $x_{2}$ respectively are joined together in a series configuration, the net extension will be

The correct option is A $x = F (1 / k_{1} + 1 / k_{2})$
$x_{1} = F / k_{1}$ and $x_{2} = F / k_{2}$
Upon joining both the springs together, the net extension will be $x = x_{1} + x_{2}$
Substituting, we get, $x = F (1 / k_{1} + 1 / k_{2})$
The correct option is (a)