If two tangents are drawn to a circle circle from an external point, the (i) they subtend equal angles at the centre (ii) they are equally inclined to the segment, joining the centre to that point.
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Solution
In ΔAPO and ΔBPO
OA=OB (radii)
AP=BP (theorem)
OP=OP (common)
ΔAPO≅ΔBPO (by SSS congruency)
by cpct,
∠AOP=∠BOP (hence, they suntend equal angle at centre P)