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Question

If two towers of height h1 and h2 subtend angles of 60° and 30° respectively at the midpoint of the line joining their feet, then show that h1 : h2 = 3 : 1.

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Solution

Let AB and CD be the two towers subtending angles 60o and 30o, respectively.
Now,
APB = 30o and ∠DPC = 60o
Let P be the midpoint of the line segment joining the two towers.
Let:
AB = h1, CD = h2 and BP = CP = x

From ∆DCP, we have:
DCPC = tan 30o = 13
h2x = 13
x = h23 ...(i)

From ∆ABP, we have:
ABBP = tan 60o = 3

h1x = 3
x = h13 ...(ii)
From (i) and (ii), we get:
h13 = h23

h1h2 = 31
h1:h2 = 3:1

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