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Question

If two triangles have equal area and stand on the same base, then the altitudes of triangle are equal.


A

1: AB-b; 2: AD-a; 3: BC-c

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B

1: AB-a; 2: AD-b; 3: BC-c

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Solution

The correct option is A

1: AB-b; 2: AD-a; 3: BC-c


Triangles on the same base (or equal bases) and having equal areas have equal altitudes.

This can be easily proved. Take two triangles: triangle-1 and triangle-2 having same base 'b' and altitudes 'c' and 'd' respectively.

Area of Triangle-1 = 12×b×c

Area of Triangle-2 = 12×b×d

Since, the triangles have same area, c = d


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