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Question

If two vertices of an isosceles triangle are (2, 0) and (2, 5) and length of the equal sides is 3 then the third vertex is

A
(2, 6) & (-5, 3)
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B
(8, 3) & (5, 1)
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C
(2±112,52)
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D
(3±142,72)
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Solution

The correct option is C (2±112,52)
GivenA(2,0),B(2,5)&C(x,y)aretheverticesofanisoscelesΔABC.TofindoutC(x,y)=?SolutionUsingdistanceformula,AB=(22)2+(05)2units=5units3units.ABisthebaseofthegiventriangle.AC=BC=3units.........(i)(x2)2+(y0)2=(x2)2+(y5)210y+25=0y=52.puttingy=52inAgainAC=BC=3units(x2)2+(y0)2=3(byi)x2+y24x+4=9.x2+y24x5=0Puttingy=52,x2+(52)24x5=04x216x+5=0x=16±1624×4×52x=2±112.C(x,y)=(2±112,52).Notethe±signofxand+signofyshowsthatthetriangleisinthefirstaswellasinthesecondquadrant.AnsOptionC.

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