wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If two volatile liquids A and B form a maximum boiling azeotrope at XA=0.3.
For, PA=200 torr and PB=400 torr ,the vapour pressure of the azeotropic mixture can exhibit a value of :


A
350 torr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
330 torr
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
360 torr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
380 torr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 330 torr
Here
XA=0.3XB=10.3=0.7
According to raoult's law :

PT=pAχA+pBχBPT=(200×0.3)+(400×0.7)PT=340 torr
Since it is a maximum boiling azeotrope,it shows negative deviation at azeotropic concentration.
The vapour pressure of the mixture will be less than as calculated from Raoult's law.
Option (b) is correct

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon