If two volatile liquids A and B form a maximum boiling azeotrope at XA - 0-3- For- P-A - 200 torr and P-B - 400 torr -the vapour pressure of the azeotropic mixture can exhibit a value of -

Here X_A=0.3 X_B=1 0.3=0.7 According to raoult's law : P_T=p^∘_Aχ_A+p^∘_Bχ_B P_T=(200× 0.3)+(400×0.7) P_T=340 torr Since it is a maximum boiling azeotrope,it ...

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Standard XII

Chemistry

Azeotropic Mixtures

If two volati...

Question

If two volatile liquids A and B form a maximum boiling azeotrope at $X_{A} = 0.3$ .
For, $P_{A}^{\circ} = 200 t o r r and P_{B}^{\circ} = 400 t o r r$ ,the vapour pressure of the azeotropic mixture can exhibit a value of :

350 t o r r

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330 t o r r

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360 t o r r

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380 t o r r

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Solution

The correct option is B $330 t o r r$
Here
$X_{A} = 0.3 X_{B} = 1 - 0.3 = 0.7$
According to raoult's law :

$P_{T} = p_{A}^{\circ} χ_{A} + p_{B}^{\circ} χ_{B} P_{T} = (200 \times 0.3) + (400 \times 0.7) P_{T} = 340 t o r r$
Since it is a maximum boiling azeotrope,it shows negative deviation at azeotropic concentration.
The vapour pressure of the mixture will be less than as calculated from Raoult's law.
Option (b) is correct

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Azeotropic Mixtures

Standard XII Chemistry

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If two volatile liquids A and B form a maximum boiling azeotrope at XA=0.3. For, P∘A=200 torr and P∘B=400 torr ,the vapour pressure of the azeotropic mixture can exhibit a value of :

If two volatile liquids A and B form a maximum boiling azeotrope at $X_{A} = 0.3$ .
For, $P_{A}^{\circ} = 200 t o r r and P_{B}^{\circ} = 400 t o r r$ ,the vapour pressure of the azeotropic mixture can exhibit a value of :