If two volatile liquids A and B forms a minimum boiling azeotrope at XA=0.5.
For P0A=400torr and P0B=500torr then choose the correct option:
Here, P0 is the vapour pressure of the azeotropic mixture .
A
P0<400torr
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B
P0=400torr
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C
400torr<P0<450torr
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D
P0>450torr
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Solution
The correct option is DP0>450torr Here XA=0.5XB=1−0.5=0.5
According to raoult's law :
PT=p∘AχA+p∘BχBPT=(400×0.5)+(500×0.5)PT=450torr
Since it is a minimum boiling azeotrope, it shows positive deviation at azeotropic concentration.
The vapour pressure of the mixture will be more than as calculated from Raoult's law.
Option (d) is correct