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Question

If two volatile liquids A and B forms a minimum boiling azeotrope at XA=0.5.
For P0A=400 torr and P0B=500 torr then choose the correct option:
Here, P0 is the vapour pressure of the azeotropic mixture .


A
P0<400 torr
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B
P0=400 torr
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C
400 torr<P0<450 torr
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D
P0>450 torr
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Solution

The correct option is D P0>450 torr
Here
XA=0.5XB=10.5=0.5
According to raoult's law :

PT=pAχA+pBχBPT=(400×0.5)+(500×0.5)PT=450 torr
Since it is a minimum boiling azeotrope, it shows positive deviation at azeotropic concentration.
The vapour pressure of the mixture will be more than as calculated from Raoult's law.
Option (d) is correct

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