If two volatile liquids A and B forms a minimum boiling azeotrope at XA - 0-5- For P0A - 400 torr and P0B - 500 torr then choose the correct option-Here- P0 is the vapour pressure of the azeotropic mixture -

Here X_A=0.5 X_B=1 0.5=0.5 According to raoult's law : P_T=p^∘_Aχ_A+p^∘_Bχ_B P_T=(400× 0.5)+(500×0.5) P_T=450 torr Since it is a minimum boiling azeotrope, it ...

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Standard XII

Chemistry

Azeotropic Mixtures

If two volati...

Question

If two volatile liquids A and B forms a minimum boiling azeotrope at $X_{A} = 0.5$ .
For $P_{A}^{0} = 400 t o r r and P_{B}^{0} = 500 t o r r$ then choose the correct option:
Here, $P^{0}$ is the vapour pressure of the azeotropic mixture .

P^{0} < 400 t o r r

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P^{0} = 400 t o r r

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400 t o r r < P^{0} < 450 t o r r

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P^{0} > 450 t o r r

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Solution

The correct option is D $P^{0} > 450 t o r r$
Here
$X_{A} = 0.5 X_{B} = 1 - 0.5 = 0.5$
According to raoult's law :

$P_{T} = p_{A}^{\circ} χ_{A} + p_{B}^{\circ} χ_{B} P_{T} = (400 \times 0.5) + (500 \times 0.5) P_{T} = 450 t o r r$
Since it is a minimum boiling azeotrope, it shows positive deviation at azeotropic concentration.
The vapour pressure of the mixture will be more than as calculated from Raoult's law.
Option (d) is correct

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Azeotropic Mixtures

Standard XII Chemistry

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If two volatile liquids A and B forms a minimum boiling azeotrope at XA=0.5. For P0A=400 torr and P0B=500 torr then choose the correct option: Here, P0 is the vapour pressure of the azeotropic mixture .

If two volatile liquids A and B forms a minimum boiling azeotrope at $X_{A} = 0.5$ .
For $P_{A}^{0} = 400 t o r r and P_{B}^{0} = 500 t o r r$ then choose the correct option:
Here, $P^{0}$ is the vapour pressure of the azeotropic mixture .