If U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}, verify that
(i) (A∪B)′=A′∩B′
(ii) (A∩B)′=A′∪B′
Here U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}
(i) A∪B = {2, 4, 6, 8} ∪ {2, 3, 5, 7}
= {2, 3, 4, 5, 6, 7, 8}
∴ (A∪B)′=U−(A∪B)
={1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 4, 5, 6, 7, 8}
= {1, 9} .........(i)
A′ = U - A
= {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 4, 6, 8}
= {1, 3, 5, 7, 9}
B′ = U - B
= {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 5, 7}
= {1, 4, 6, 8, 9}
A′∩B′ = {1, 3, 5, 7, 9} ∩ {1, 4, 6, 8, 9}
= {1, 9} .......(ii)
From (i) and (ii), we have
(A∪B)′=A′∩B′
(ii) A∩B = {2, 4, 6, 8} ∩ {2, 3, 5, 7} = {2}
(A∩B)′=U−(A∩B)
= {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2}
= {1, 3, 4, 5, 6, 7, 8, 9} .........(i)
A′ = U - A
= {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 4, 6, 8}
= {1, 3, 5, 7, 9}
B′ = U - B
= {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 5, 7}
= {1, 4, 6, 8, 9}
A′∪B′ = {1, 3, 5, 7, 9} ∪ {1, 4, 6, 8, 9}
= {1, 3, 4, 5, 6, 7, 8, 9} .......(ii)
From (i) and (ii), we have
(A∩B)′=A′∪B′