If $U = {1, 2, 3, 4, 5, 6}$ and $A = {2, 3, 4, 5}$ then find $A^{'}$ .

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Solution

$U = {1, 2, 3, 4, 5, 6}$ & $A = {2, 3, 4, 5}$
$A^{'}$ is compliment of $A$
by using the property of compliment: $A$ $\cup$ $A^{'} = U$
So the elements in U other than $A$ are the elements of $A^{'}$
So $A^{'} = 1, 6$

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